can anyone help me to construct this matrix
blj=(-2)^j-l if l<j
blj=1 if l=j
blj=0 if l>j

 Réponse acceptée

Brian Hart
Brian Hart le 22 Déc 2018
Modifié(e) : Brian Hart le 22 Déc 2018

0 votes

Hi diadalina,
I think it would look something like this...
iLength = 5; %rows
jLength = 7; %cols
b=zeros(iLength, jLength);
for i = 1:iLength
for j = 1:jLength
if i == j; b(i,j) = 1; end
if i < j; b(i,j) = (-2)^(j-i); end
end
end
disp(b)
gives a result of:
1 -2 4 -8 16 -32 64
0 1 -2 4 -8 16 -32
0 0 1 -2 4 -8 16
0 0 0 1 -2 4 -8
0 0 0 0 1 -2 4

2 commentaires

Guillaume
Guillaume le 22 Déc 2018
It is unclear if the formula in the question is as written or which would make more sense. One thing for sure, it's not likely to be which is what you calculate.
Brian Hart
Brian Hart le 22 Déc 2018
Yep, missed a set of parenthesis. Corrected, thanks.

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Plus de réponses (2)

Guillaume
Guillaume le 22 Déc 2018
Modifié(e) : Guillaume le 22 Déc 2018

1 vote

Assume your formula is and not what you have written:
nrows = 5; %number of rows. You haven't specified
ncols = 7; %number of columns. You haven't specified
b = toeplitz([1, zeros(1, nrows-1)], (-2).^(0:ncols-1))
If the formula is what you have actually written, , then
b = triu((-2).^(1:ncols) - (1:nrows)', 1) + eye(nrows, ncols)
Stephan
Stephan le 22 Déc 2018
Modifié(e) : Stephan le 22 Déc 2018

0 votes

Hi,
do you want a square matrix? Is the calculation correct without any brackets? My calculation follows the way you wrote the formula - if wrong set the brackets corresponding to your expected result.
Then try:
k=3;
[m,n]=meshgrid(1:k);
A=triu((-2).^n-m,1) + eye(k)
Best regards
Stephan

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