if in a row i am having 6 numerical values of large number i want convert into binary form of length 10 bits

in a row for example 4351 890 2312 9045 234 50 i want to convert into binary form with length of 10 bits, generally i can use dec2bin code but getting for one numerical value i want to get to all six numerical

Answer 1

[Stephen23]

>> V = [234,567,123,456,900,190];
>> M = dec2bin(V(:),10)
M =
0011101010
1000110111
0001111011
0111001000
1110000100
0010111110

Each row represents one of the input numbers.

[rajesh kumar]

thanq

[Walter Roberson]

Note the result will be a char array. Those 0 and 1 that show up are '0' and '1' not numeric 0 and 1. Using '0' and '1' is fine for a number of purposes, but using numeric 0 and 1 is more versatile.

Answer 2

[Walter Roberson]

reshape((dec2bin(theVector,10)-'0').', 1, [])

[rajesh kumar]

getting error what u have senede, sir i am having data

234 567 123 456 900 190

like this i want to convert into binary for

10001101001 1000101010 1010101010 1111100000 1010101010 00001010101

like this and store in a variable. generally if i am having 10 values in a row i can use V(1,i) where i=1 to 10, but for bianry how to store

[rajesh kumar]

my question is how to convert into bianry form and how to store in avariable

[Walter Roberson]

The code I gave converts them values to binary with length 10 bits, and puts the result all in one vector, which is what people usually want to do when they convert a vector of numbers.