I'm trying to create a binary to unary encoding converter. However I am getting stuck on one of the final loops. Which should print out the number of ones for the positional value. After this I plan on adding the resulting matrices together.

A=[1 0 1];

l=length(A);

un = zeros(1, l);

for N = 1:l %position is (N-1)

% B=A(N:end); ignore

un(N)=(2^(N - 1));

mul= un .* A; %find positional value

%Unary = zeros(1, mul);

for i = 2:mul %error here, needs to be a scalar value

Unary(i)= i./i; %therfore unary gets defined as '1' stuck on first iteration i think

end

end

%paper for reference to unary; https://ieeexplore.ieee.org/stamp/stamp.jsp?tp=&arnumber=8309178

Answer 1

[Vishal Chaudhary]

In the second for loop, since, mul is array, try using mul(N) to access the elements and change the logic accordingly. I think a better way would be to convert to decimal first and then make array of 1's which will be required unary conversion. Something like below:

A=[1 0 1];
deci = bi2de(A);
unary = ones(1,deci);