How I can create a three dimensional succession

1 vue (au cours des 30 derniers jours)
ric1321
ric1321 le 6 Jan 2019
Commenté : Stephen23 le 6 Jan 2019
Hi to everyone! What I would like to know is how I can define a 1x1xN element considering that in the third dimension I would like to have something like:
freq = (5:0.5:15)*1e9;
I hope I've been clear enough!

Réponse acceptée

Stephan
Stephan le 6 Jan 2019
freq(1,1,:) = (5:0.5:15)*1e9;
  2 commentaires
ric1321
ric1321 le 6 Jan 2019
Thank you!
Stephen23
Stephen23 le 6 Jan 2019
Note that this is fragile, and can throw an error if freq already exists in the workspace and has an incompatible size.

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Plus de réponses (2)

John D'Errico
John D'Errico le 6 Jan 2019
Modifié(e) : John D'Errico le 6 Jan 2019
As simple as one line like this:
freq = reshape((5:0.5:15)*1e9,1,1,[]);
As you can see, it has the desired shape.
size(freq)
ans =
1 1 21

madhan ravi
madhan ravi le 6 Jan 2019
N=numel(freq);
f=zeros(1,1,N);
f(:,:,:)=freq

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