for 1:x with unkonw x
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Riccardo Rossi
le 7 Jan 2019
Commenté : Riccardo Rossi
le 7 Jan 2019
Hi everybody,
i have an array like this:
ARRAY
X Y Z C
-3 4 5 1
5 6 2 2
4 4 9 1
6 6 7 2
4 6 2 3
9 9 7 3
where C goes from 1 to x (x unknow). I want to create a for to have x arrays with XYZ associated with C, like this:
for k=1:x
A(1:k)=[ARRAY(:,1),ARRAY(:,2),ARRAY(:,3),ARRAY(:,4)==1:k]
end
A1
X Y Z
-3 4 5
4 4 9
A2
X Y Z
5 6 2
6 6 7
A3
X Y Z
4 6 2
9 9 7
Thank you!
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Réponse acceptée
madhan ravi
le 7 Jan 2019
Modifié(e) : madhan ravi
le 7 Jan 2019
Don't think of naming variables dynamically (https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval ) use cell instead:
a=[-3 4 5 1
5 6 2 2
4 4 9 1
6 6 7 2
4 6 2 3
9 9 7 3];
u=unique(a(:,4));
A=cell(1,numel(u));
for i = 1:numel(u)
idx = (a(:,4) == u(i)); % edited after Jan's comment
% idx=ismember(a(:,4),u(i));
A{i}=a(idx,1:3);
end
celldisp(A)
Gives:
A{1} =
-3 4 5
4 4 9
A{2} =
5 6 2
6 6 7
A{3} =
4 6 2
9 9 7
5 commentaires
madhan ravi
le 7 Jan 2019
Modifié(e) : madhan ravi
le 7 Jan 2019
Anytime :)
mean_of_X_Y_Z_in_each_cell=cellfun(@mean,A,'un',0)
Plus de réponses (1)
KSSV
le 7 Jan 2019
A = [-3 4 5 1
5 6 2 2
4 4 9 1
6 6 7 2
4 6 2 3
9 9 7 3 ] ;
C = A(:,end) ;
[c,ia,ib] = unique(C) ;
N = length(c) ;
iwant = cell(N,1) ;
for i = 1:N
iwant{i} = A(C==c(i),1:3) ;
end
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