how to convert cell 10X8 to mattrix and matrix 10X8 to to 8 bit value [1,1,1,1,0,0,0,0]

Fs=10;
Ts=1/Fs;
L=10;
t=(0:L-1)*Ts;
% ms1=sin(2*pi*50*t);
% ms2=cos(2*pi*50*t);
ms1=sawtooth(2*pi*50*t);
%% analog to digital
no_of_bit=8;
q_level=50/(2^(no_of_bit)-1);
msg1_abs=abs(ms1);
msg_0=fix(msg1_abs/q_level);
digit_ms1=dec2bin(msg_0,no_of_bit);

v=cell2mat([{digit_ms1(:,:,:)}]); 
v1=str2num(v);   %%%% THIS is giving coulm bits but  I want 8 bit data in bit format to used it as 8 bit i.e [1,1,1,1,0,0,0,0]    

[Walter Roberson]

just take the result of dec2bin and subtract '0' which is the character for the digit 0.

Answer 1

[Luna]

Hi,

Just try this:

v = logical(digit_ms1 - '0');  % if you want bits logical use logical otherwise it will give you double array

[Bablu Singh]

THANK YOU IT WAS HELPFUL..

Can you Please tell me how to get the ms1 signal again after getting converting to

v = (digit_ms1 - '0');

I want to do reverse process for above metion code please help

[Walter Roberson]

recovered = char(v + '0');

[Bablu Singh]

helo sir

I need to recover ms1 sawtooth back from V %% ms1=sawtooth(2*pi*50*t);

i.e digital to sawtooth

plz help