Implementing interparc function for dividing arc to segments

I want to divide an arc to equal segments. I found a function called as https://in.mathworks.com/matlabcentral/fileexchange/34874-interparc, which can perform this. But i am slightly confused by the implementation. For eg: In the code below, i am trying to divide the arc in to 25 equal sections, What i want to know is whether each section have equal arc length. Any help to solve this will be appreciated.

px  = X_coord_req; % X-values
py  = Y_coord_req; % Y-values
pt = interparc(25,px,py,'pchip');          % do this this mean the arc is divided to 25 segments of equal arc length?
plot(px,py,'r',pt(:,1),pt(:,2),'b-o') 
ax = gca;
ax.YDir = 'reverse';
axis([0 6600 0 5000])

[Hari krishnan]

Can anyone give an explanation to this?

[Walter Roberson]

Yes each section will have equal arc length.

[Hari krishnan]

@Walter Robinson . Thank you very much