How to fill matrix in for loop?

I need to fill matrix r, where r=r(z), and ri is constant. But with this code I onlu get the first row where r=-0.7:0.7.

z=-1:0.001:0;
ri=0.7;
R=ri-z*(ri-1);
for z=-1:0.001:0;
r=(linspace(-(ri-z*(ri-1)),ri-z*(ri-1),1001))
end

My full matrix need to be in this shape, or transpose of this:

-0.7......  0.7

0.8  ...    0.8
.            .
.            .
.            .
0 .9 ...     0.9
.            .
.            .
.            .
1     ...    1

Answer 1

[Stephen23]

>> (0.7:0.05:1).'*(0:0.2:1)
ans =
   0.00000   0.14000   0.28000   0.42000   0.56000   0.70000
   0.00000   0.15000   0.30000   0.45000   0.60000   0.75000
   0.00000   0.16000   0.32000   0.48000   0.64000   0.80000
   0.00000   0.17000   0.34000   0.51000   0.68000   0.85000
   0.00000   0.18000   0.36000   0.54000   0.72000   0.90000
   0.00000   0.19000   0.38000   0.57000   0.76000   0.95000
   0.00000   0.20000   0.40000   0.60000   0.80000   1.00000

Adjust the step sizes to suit your requirements.

Answer 2

[KSSV]

z=-1:0.001:0;
ri=0.7;
R=ri-z*(ri-1);

[R,Z] = meshgrid(z,R) ;
r = R-Z.*(R-1) ;

[I G]

This does not work for me because I got matrix with values from 0.7 to 1 in this shape:

1    1     ....   1
.
.
1    0.997  .... 0.7

and it need to be with these values:

-0.7......  0.7
-0.8  ...   0.8
.            .
.            .
.            .
-0.9 ...    0.9
.            .
.            .
.            .
-1     ...   1

or with values:

0   ......  0.7
0    ...    0.8
.            .
.            .
.            .
0  ...      0.9
.            .
.            .
.            .
0     ...    1