How do I turn my function into a column vector?
Afficher commentaires plus anciens
I'm trying to solve a second-order differential equation using matlab, but for some reason I keep getting the error message that my function should be a column vector.
I'm calling the function (tryagain) from the following script (wilyourunnow):
clear all %Remove stray stuff
ht = linspace(0,10,1001);
h = sin(ht);
%This is based on the instructions as given in the help browser on the page
%for ode45; tab ODE with Time-Dependent Terms
[t,x] = ode45(@(t,x)'tryagain', (0:0.01:10), [0 1]);
plot(t,x)
And this is the function:
function dxdt = tryagain(t,x,ht,h)
h=interp1(ht,h,t);
dxdt = zeros(2, 1);
dxdt(1)= x(2);
dxdt(2) = -x.^2 + x + h;
When I try to run the script, I get the following error:
>> wilyourunnow
Error using odearguments (line 93)
@(T,X)'TRYAGAIN' must return a column vector.
Error in ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in wilyourunnow (line 10)
[t,x] = ode45(@(t,x)'tryagain', (0:0.01:10), [0 1]);
I've already tried transposing the vector with these two commands (separately)
dxdt = transpose(dxdt)
dxdt = dxdt(:)
Réponse acceptée
Plus de réponses (0)
Catégories
En savoir plus sur Programming dans Centre d'aide et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
