how to identify the user number with respect to the following code in the attached graph.

clear all;
clc;
user=2
subcarrier=4
for t = 1:length(user)
    radius=3
    X=ones(1,user(t))
    Y=ones(1,user(t))
    R=radius*(rand(1,user(t)))
    th = 0:pi:2*pi
    X1=X+R
    Y1=Y+R
    xaxis = radius * cos(th)
    yaxis = radius * sin(th)
    figure
    plot(xaxis, yaxis)
    hold on
    plot(Y,X,'r^')
    hold on
    plot(Y1,X1,'ko')
    hold on
    c=2*pi
    for r = 1:length(subcarrier)
        for j=1:user(t)
            temp=[];
            for n=1:subcarrier(r)
                nc=(n-1)*c;
                entry=(1+i*nc)/(1+nc^2);
                temp=[temp entry]
            end
            G=randn(subcarrier(r),1)+i*randn(subcarrier(r),1)
            H=abs(G)
            figure
            plot(abs(H),'-*')
            hold on
            
        end
    end
end

The above code executes and gives me the attached graph.

From the fig 1 how to identify which is user 1 and user 2.

and from fig2 and fig 3 which is for user 1 and user 2.

[Rik]

Your code is really confusing, because it lacks comments about what it should be doing. You also don't explain what it is you mean. We are not mind readers, you need to explain these things. This is not your first question.

There are also numerous issues in this code. The debugging tools are really valuable, try to use them. Because of the many times you omit the semicolon, it is not visible at a glance if there are any other issues that were automatically detected.

One of the things you are missing now is that you're using j as a loop index, but then use i in your code. I don't know if that is an error, but it seems odd you wouldn't be using your loop index variable for anything. Avoid i and j as variables to avoid any ambiguity and use 1i to generate the complex unit value.