Effacer les filtres
Effacer les filtres

How to extract minimum values in a row and replace them with their variable?

3 vues (au cours des 30 derniers jours)
Alayt Abraham Issak
Alayt Abraham Issak le 18 Jan 2019
I have four colums and 928 rows in a table. I would like to extract the smallest number in each row and replace it with the variable (title/name) at the top of the column in which the value came from.
I have managed to extract the smallest number by changing the table into an array. However, I was not able to change that small value into the name of the column. Moreover, I do not prefer changing the table into arrays becasue I would like to have my final result in a table format.
How may I do so? Find the smallest value in a row and replace it with its title in a table?
  8 commentaires
Alayt Abraham Issak
Alayt Abraham Issak le 21 Jan 2019
I'm quite new and did not know how to do that, that's why I changed it directly to array.
Alayt Abraham Issak
Alayt Abraham Issak le 22 Jan 2019
Also, the code outputs "1".

Connectez-vous pour commenter.

Réponses (1)

Kevin Phung
Kevin Phung le 18 Jan 2019
Modifié(e) : Kevin Phung le 18 Jan 2019
If you want to have both numeric and strings in your table, those table elements will have to be cell arrays.
for example, if you have :
a = {1 2 3 4 5}; % your data values, stored in cells.
table1 = table(a',a',a')
tableVarNames = {'a','b','c'}; %your column names
table1.Properties.VariableNames = tableVarNames
to change a table element from numeric to a string, running :
table1{1,3} = tableVarNames(1)
will give you:
table1 =
5×3 table
a b c
___ ___ ___
[1] [1] 'a'
[2] [2] [2]
[3] [3] [3]
[4] [4] [4]
[5] [5] [5]
So something like this will find the minimum for each row and replace it with variable names:
for i = 1:size(table1,1)
[M,I] = min(cell2mat(table1{i,:})) %M is the minimum value, I is the indice
table1{i,I} = tableVarNames(I); %changes that value to a variableName
end
  4 commentaires
Alayt Abraham Issak
Alayt Abraham Issak le 21 Jan 2019
No, the loop did not work. I've written a detailed repsonse on the comment above.
Kevin Phung
Kevin Phung le 21 Jan 2019
You got the error because your AB table needs to be cell arrays.
Can you try table2cell for your ABTable.
so:
ABTable = table2cell(Subset) % this is now a matrix of cells, NOT a table
tableVarNames = {'Plmt','S107','S108','S11','S112'} % your variable names
for i = 1:size(ABtable,1)
[M,I] = min(cell2mat(ABtable{i,:})) %M is the minimum value, I is the indice
Subset{i,I} = tableVarNames(I); %makes changes to your main table, Subset
end

Connectez-vous pour commenter.

Catégories

En savoir plus sur Tables dans Help Center et File Exchange

Tags

Produits


Version

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by