Displaying the most number of counts
1 vue (au cours des 30 derniers jours)
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A=
'' 'c1' 'c2' 'c3' 'c4' 'c5'
'yar12' 'hi' 'hello' 'hi' 'hello' 'hi'
'yar13' hello' 'hi' 'hi' 'hello' 'hi'
'yar14' 'hi' 'hi' 'hi' 'hello' 'hello'
'yar15' 'hello' 'hi' 'hi' 'hi' 'hi'
'yar16' 'hello' 'hi' 'hi' 'hello' 'hello'
'yar17' 'hi' 'hi' 'hi' 'hi' 'hi'
With respect to c1 i want to display only the same value(as c1 value) having more than 2 counts for example
'yar12' has 'hi'(considering c1 as value) thrice(c1 to c5) so i want to display
'yar12' 'hi' 'hello' 'hi' 'hello' 'hi'
yar13 should no be considered because its has 'hello'(considering c1 as value) twice (from c1 to c5)twice,so i need output as
'yar12' 'hi' 'hi' 'hi'
'yar14' 'hi' 'hi' 'hi'
'yar16' 'hello' 'hello' 'hello'
'yar17' 'hi' 'hi' 'hi' 'hi' 'hi'
please provide assistance
6 commentaires
Jan
le 20 Juil 2012
The similarities between kash's and Pat's question are surprising. @Pat and kash: Are you working on the same problem?
Walter Roberson
le 20 Juil 2012
In the past, kash and Pat were taking exactly the same course at the same location (they indicated), and yet their assignments were not always exactly the same. My speculation would be that they are still taking the same course together but that the instructors give each student slightly different assignments.
Réponse acceptée
Thomas
le 19 Juil 2012
A very round about way of doing this but works..
a = { '' 'c1' 'c2' 'c3' 'c4' 'c5'
'yar12' 'hi' 'hello' 'hi' 'hello' 'hi'
'yar13' 'hello' 'hi' 'hi' 'hello' 'hi'
'yar14' 'hi' 'hi' 'hi' 'hello' 'hello'
'yar15' 'hello' 'hi' 'hi' 'hi' 'hi'
'yar16' 'hello' 'hi' 'hi' 'hello' 'hello'
'yar17' 'hi' 'hi' 'hi' 'hi' 'hi'};
for count=2:size(a,1)
out(count,:)=strcmp(a(count,:),a(count,2));
check_sum(count)=sum(out(count,:));
end
output=a(check_sum>2,:);
p=out(check_sum>2,:)
p(:,1)=1;
[r,c]=find(p==1);
for ii=1:length(r)
a=r(ii);
b=c(ii);
final(a,b)=output(a,b);
end
final
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