fplot(@(x) x*(sin(x))^2*cos(x),[-2*pi 2*pi]);
[xMin1 fvalmin1] = fminbnd('-x*(sin(x))^2*cos(x)', -6, 6)
returns xMin1 = 1.0954
fvalmin1 = -0.3963
How is this possible, look at the plot?

3 commentaires

madhan ravi
madhan ravi le 20 Jan 2019
Why do you say it's a bug?
Stephen Wilkerson
Stephen Wilkerson le 20 Jan 2019
Not where the minimum is! look at the plot
Stephen Wilkerson
Stephen Wilkerson le 20 Jan 2019
Solved, The function doesn't really do much, it give you the nearest point that's a minimum to it's starting point. In my case it woud be 0 as the starting point. Typical

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 Réponse acceptée

Walter Roberson
Walter Roberson le 20 Jan 2019

0 votes

No bug. fminbnd is a local minimizer, not a global minimizer.

3 commentaires

Zhe Yu
Zhe Yu le 17 Juil 2022
Modifié(e) : Torsten le 17 Juil 2022
Hi Roberson,
I have a similar problem with fminbnd, see code below
a=-200; b=-979.8997; c=7.1833e+05; d=24.4232;e=-6.6083;
x1=0; x2=4.1135e-06;
f=@(x)a-(a-b)*cos(c*(x-x1)) + d*e*sin(c*(x-x1))
f = function_handle with value:
@(x)a-(a-b)*cos(c*(x-x1))+d*e*sin(c*(x-x1))
fplot(f, [x1 x2])
[xmin, min]=fminbnd(f, x1, x2)
xmin = 1.5712e-06
min = -679.5775
We could see from the plot the minimum value should be around -996 and there should be only one local minimum. But fminbnd returns -679.
Thanks a lot in advance!
Best Regards,
Zhe
Torsten
Torsten le 17 Juil 2022
Modifié(e) : Torsten le 17 Juil 2022
Since the changes in the x-values are in the order of 1e-6, you must choose a smaller value for TolX:
a=-200; b=-979.8997; c=7.1833e+05; d=24.4232;e=-6.6083;
x1=0; x2=4.1135e-06;
f=@(x)a-(a-b)*cos(c*(x-x1)) + d*e*sin(c*(x-x1))
f = function_handle with value:
@(x)a-(a-b)*cos(c*(x-x1))+d*e*sin(c*(x-x1))
fplot(f, [x1 x2])
options = optimset('TolX',1e-8);
[xmin, min]=fminbnd(f, x1, x2, options)
xmin = 2.8422e-07
min = -996.4246
Zhe Yu
Zhe Yu le 17 Juil 2022
Hi Torsten, thank you very much!

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