Error in following matlab code.

Error in following codes
for i = 1:12
if i == 12
x1 = 9
end
x1 = [1];
x2 = [3];
if i == 1
x1 = 2
else
x1(i) = x1(i-1) - x2;
end
x = [x1 x2]
end
When i run it it shows following error please help me to solve error.
Array indices must be positive integers or logical values.

3 commentaires

madhan ravi
madhan ravi le 26 Jan 2019
Modifié(e) : madhan ravi le 26 Jan 2019
What is your desired result ? Give an example.
Usman Taya
Usman Taya le 26 Jan 2019
I want 12 values of x1 and x2 where current x1 from i = 2 to 12 will calculate using x1(i) = x(i-1) -x2.
Image Analyst
Image Analyst le 3 Fév 2019
Yes, but did Star's answer below solve your problem or not? Did you even try it?

Connectez-vous pour commenter.

Réponses (1)

Star Strider
Star Strider le 26 Jan 2019

0 votes

The error comes from your current calculation of ‘x1’ as:
x1(i) = x1(i-1) - x2;
In the first iteration,i=1 so (i-1)=0. In MATLAB, indices are integers greater than 0, or logical values.
I am not certain this ‘corrected’ version of your code creates the values for ‘x’ that you want. However, it has the virtue of running without error:
for i = 1:12
if i == 12
x1(i) = 9;
end
x1(i) = [1];
x2 = [3];
if i == 1
x1(i) = 2;
else
x1(i+1) = x1(i) - x2;
end
x(i,:) = [x1(i) x2];
end
Experiment to get the result you want.

Catégories

En savoir plus sur Operators and Elementary Operations dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by