invers matrix error calculate
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OA=1.42
AB=4.3
BO=3.33
OO=6
alfa=linspace(19.7, -103, 14);
beta= [37.3648, 40.5764, 43.6511, 46.4267, 48.7411, 50.4573, 51.4816, 51.7706, 51.3269, 50.1884, 48.4165, 46.0853, 43.2749, 40.0669];
gamma= [-68.0355, -66.333, -63.8261, -60.6513, -56.9882, -53.0279, -48.9467, -44.8871, -40.9515, -37.2048, -33.6824, -30.3996, -27.3598, -24.5623]
J=[AB*sind(beta) BO*sind(gamma); AB*cosd(beta) BO*cosd(gamma)]
omega=(inv(J))*[OA*sind(alfa); OA*sind(alfa)]
disp(omega)
It calculates:
OA =
1.4200
AB =
4.3000
BO =
3.3300
OO =
6
gamma =
-68.0355 -66.3330 -63.8261 -60.6513 -56.9882 -53.0279 -48.9467 -44.8871 -40.9515 -37.2048 -33.6824 -30.3996 -27.3598 -24.5623
J =
Columns 1 through 16
2.6096 2.7970 2.9681 3.1153 3.2325 3.3159 3.3644 3.3778 3.3571 3.3031 3.2164 3.0976 2.9476 2.7678 -3.0883 -3.0499
3.4176 3.2660 3.1113 2.9639 2.8357 2.7376 2.6779 2.6609 2.6870 2.7531 2.8540 2.9824 3.1307 3.2908 1.2455 1.3367
Columns 17 through 28
-2.9885 -2.9026 -2.7924 -2.6604 -2.5111 -2.3500 -2.1825 -2.0135 -1.8468 -1.6851 -1.5304 -1.3842
1.4689 1.6321 1.8142 2.0027 2.1870 2.3593 2.5150 2.6523 2.7710 2.8722 2.9575 3.0287
Error using inv
Matrix must be square.
Error in accelerazioniangolari (line 9)
omega=(
How can i solve the error, it calculates J not like 14 matrix, i think that is the problem. How can i fix it?
2 commentaires
John D'Errico
le 3 Fév 2019
Modifié(e) : John D'Errico
le 3 Fév 2019
https://www.mathworks.com/matlabcentral/answers/442898-how-to-find-the-inverse-of-a-6-2-matrix
Réponses (1)
John D'Errico
le 3 Fév 2019
You cannot use inv on a 2x28 array. So either of these forms are equally valid:
omega=pinv(J)*[OA*sind(alfa); OA*sind(alfa)];
omega=J\[OA*sind(alfa); OA*sind(alfa)];
Neither is more technically coerrect, and you can take your free choice between which of infintely many solutions you want. The two options above are just two of the many possible.
2 commentaires
John D'Errico
le 3 Fév 2019
You cannot assume that MATLAB will be smart enough to figure out what you want to do, when you try to do something completely unusual. Instead, MATLAB does what you tell it to do, and can do no more than that.
However, nothing stops you from using a loop. Loops are not the worst thing in the world. They are not that inefficient.
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