In need of decreasing exponential smooth curve

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Abhinandana R
Abhinandana R le 10 Fév 2019
Commenté : Abhinandana R le 10 Fév 2019
u=0.3; pi=22/7; g=80;
l=20; d=10; p=1;
r=linspace(0,1,10);
m=tand(p)
a=(r-m*(d+l)).^-2-((r-m*l).^-2)
q=(pi*r.^4*g)/(8*u*l)
t=(2*u*q.*a)/(pi*m)
plot(r,t)
I need a decreasing smooth exponential curve. please help me

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Stephan
Stephan le 10 Fév 2019
Modifié(e) : Stephan le 10 Fév 2019
Your linspace call will lead to 10 results calculated in the interval of 0...1. If you leave the 10 away, the standard is 100 values, which gives a smoother curve:
u=0.3; g=80;
l=20; d=10; p=1;
r=linspace(0,1);
m=tan(p);
a=(r-m*(d+l)).^-2-((r-m*l).^-2);
q=(pi*r.^4*g)/(8*u*l);
t=(2*u*q.*a)/(pi*m);
plot(r,t)
You should also do not overwrite pi - it is a constant in Matlab - no need to define it.
Best regards
Stephan
  3 commentaires
Stephan
Stephan le 10 Fév 2019
Modifié(e) : Stephan le 10 Fév 2019
what about
m=exp(p)
for the interval 0...1 it is a smooth decreasing curve. That is the desired result?
Abhinandana R
Abhinandana R le 10 Fév 2019
yeah thanks !

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