FFT of Rectangular Window

Hi,
I want to calculate the phase of a Rectangular window with width T and shifted by T0. I was expecting the slope of the phase to be -T0. Unfortunately, I am getting the slope as -(T0 - T/2). Can someone explain the mistake in my code attached.
T0 = 50;
T = 20;
x = (0:0.1:100);
y = 1 * (x>=(T0 - T/2) & x <= (T0 + T/2));
N = 2 ^ nextpow2(length(x));
Fs = 1/mean(diff(x));
w_axis = linspace(0, Fs, N) * 2 * pi;
fft_y = fft(y, N);
ang = unwrap(angle(fft_y));
mag = abs(fft_y);
index = 1:N/2;
mag = mag(index);
ang = ang(index);
w_axis = w_axis(index);
subplot(2, 2, [2, 4]);plot(x, y);
subplot(2, 2, 1);plot(w_axis, mag);
subplot(2, 2, 3);plot(w_axis, ang);
p = polyfit(w_axis, ang, 1);
fprintf('Slope of phase = %3.3f\n', p(1));

Réponses (0)

Catégories

En savoir plus sur Fourier Analysis and Filtering dans Centre d'aide et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by