Creating possible addition of a number

2 vues (au cours des 30 derniers jours)
fyza affandi
fyza affandi le 24 Fév 2019
Commenté : fyza affandi le 24 Fév 2019
I have a set of array A
A= [1 2 4 8 16]
For example I want a set of number that make up total of 4 (from A), it would be
B=[1 1 1 1] *total in array B would be 4*
B=[1 1 2]
B=[2 2]
B=[4]
Is it possible to do it in Matlab?
  1 commentaire
Rik
Rik le 24 Fév 2019
It is possible to this in Matlab. How would you try to solve it?

Connectez-vous pour commenter.

Réponse acceptée

John D'Errico
John D'Errico le 24 Fév 2019
Modifié(e) : John D'Errico le 24 Fév 2019
Trivial, if you download my partitions function from the File Exchange.
A = [1 2 4 8 16];
partitions(4,A)
ans =
4 0 0 0 0
2 1 0 0 0
0 2 0 0 0
0 0 1 0 0
Each row of the result tells you how many times that element appears in the target sum.
Find it here:
Note that the number of such partitions can be immense for some problems. You can easily overwhelm such a tool. For example, I have another utiility that will count the number of partitions of an integer.
numberOfPartitions(1000)
ans =
24061467864032622473692149727991
Thus as the sum of numbers in the set [1:1000]. It gets big, and does so pretty fast.

Plus de réponses (1)

Stephen23
Stephen23 le 24 Fév 2019
Download John D'Errico's excellent partitions:
and use it like this:
>> A = [1,2,4,8,16];
>> M = partitions(4,A);
>> F = @(v)repelem(A,v);
>> C = cellfun(F,num2cell(M,2),'uni',0);
>> C{:}
ans =
1 1 1 1
ans =
1 1 2
ans =
2 2
ans =
4
  2 commentaires
John D'Errico
John D'Errico le 24 Fév 2019
One of the things I should have added as an option, was the ability to return the partitions in an expanded form, something much like Stephen did here. You can never have too many options in an interface. Well, at least not until you do. ;-)
fyza affandi
fyza affandi le 24 Fév 2019
Thank you very much :)

Connectez-vous pour commenter.

Catégories

En savoir plus sur Multidimensional Arrays dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by