HOW TO CREATE THİS MATRİX

100x100 matrix

0 1 2 ....... 99

1 2 3 ....... 100

2 3 4 ....... 101

. . . ........ .......

. . . ....... ........

. . . ....... .......

99 100 101 102 ..... 198

[HilaN]

a=[];
N=100;
T=N;
for i=1:N
    a(i,:) = [i-1:1:T-1];
    T=T+1;
end

[MERT METIN]

no right run

[HilaN]

why not? this is the matrix you wanted, or I didn't got right what you are asking..

Answer 1

[Stephan]

Hi,

beginning from R2016b you can use:

A = [0:99] + [0:99]'

or - with respect to Madhans comment for prior releases:

B = bsxfun(@plus, [0:99], [0:99]')

Best regards

Stephan

[MERT METIN]

no :(

[Stephan]

Whats wrong with it? For me it gives exactly the result you wanted. So please clarify.

[MERT METIN]

ıt is my homework and this solution is not basic. I need basic solution. we dont learn bsxfun function :(

[MERT METIN]

my Matlab version is 2018b

[Stephan]

A = [0:99] + [0:99]'

is basic - it could not be more basic... But i guess you have to write something like a loop.

[madhan ravi]

People here don’t do obvious homework problems, come up with the code that you have tried.

[Stephan]

Madhan is right. Show your attempts so far and tell us where your secific problems are.

[MERT METIN]

this question is not only one. ı have another questions from homework but ı did others. Just this question ı did not. Thank you for everything.

Answer 2

[madhan ravi]

Just add the column vector which goes from 0 to 99 (step size 1) with the row vector which also has the same starting point and ending point as same as the column vector (step size 1).

doc colon

[madhan ravi]

If your version is prior to 2016b use bsxfun() with plus.

Answer 3

[Andrei Bobrov]

hankel(0:99,(0:99)+99);

[MERT METIN]

not completely true