I have the following code:
for x = 1:0.01:1.5
z = g(x,rpf);
end
but when I run this (assume my function is correct), I only get that z is equivalent to the last data point. How can I store x and z in a matrix and then plot them?

 Réponse acceptée

Bob Thompson
Bob Thompson le 5 Mar 2019

0 votes

You need to index z with each loop.
count = 0;
for x = 1:0.01:1.5;
count = count + 1;
z(count) = g(x,rpf);
end
plot(x,z)

7 commentaires

Benjamin
Benjamin le 5 Mar 2019
Modifié(e) : Benjamin le 5 Mar 2019
This only has one value for x and z looks like it is produced as a row vector, not a column
Bob Thompson
Bob Thompson le 5 Mar 2019
Are you saying that z is a 2D array?
Plot should work no matter if x and z are row or column vectors, they just have to be 1D.
Benjamin
Benjamin le 5 Mar 2019
when i run this code, x is 1x1, not 51x1
Bob Thompson
Bob Thompson le 5 Mar 2019
Modifié(e) : Bob Thompson le 5 Mar 2019
Mmm, I apologize. I get overzealous with my responses some times and miss things.
plot([1:0.01:1.5],z)
Benjamin
Benjamin le 5 Mar 2019
yeah, I mean I figured it out, I just set x=1:0.01:1.5 after the loop and before the plot command. was just noting that that plot command as it was could not explicitly be used. thanks for the help!
Benjamin
Benjamin le 5 Mar 2019
Modifié(e) : Benjamin le 5 Mar 2019
Can I ask a follow-up? How could I do an outer loop for different values of rpf and then plot each one on the same plot? And the values for rpf would be like specific values: (i.e. 5.4, 6.7, 5.2 etc) Any ideas how I would do this? When I try it, it just keeps adding move rows to z, rather than just overwriting it on the next loop
Benjamin
Benjamin le 5 Mar 2019
I created a new question, maybe you could answer this question there.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by