How to run lsqcurvefit with a function handle with 2 array-variables?

For an easy reference I placed a provided Mathworks example below.
xdata = [0.9 1.5 13.8 19.8 24.1 28.2 35.2 60.3 74.6 81.3];
ydata = [455.2 428.6 124.1 67.3 43.2 28.1 13.1 -0.4 -1.3 -1.5];
fun = @(x,xdata)x(1)*exp(x(2)*xdata);
x0 = [100,-1];
x = lsqcurvefit(fun,x0,xdata,ydata)
I'll start off by mentioning that I am unfamiliar with creating a function handle with an array as a variable as you see with "xdata" which partially leads to my confusion. My issue is that my function has an additional array variable. "k" are my coefficients I'm solving for using lsqcurvefit while "C_TBA_H2O," "C_H2O" are arrays of data points. My x-axis for evaluation is in terms of "C_TBA_H2O." Any clarification or explanation on how to set this up would be greatly appreciated.
rao_H2O = @(k, C_TBA_H2O, C_H2O) k(1)*k(2)*C_TBA_H2O/(1+k(2)*C_TBA_H2O+(k(2)*C_H2O)^gamma(2))+k(3)*C_TBA_H2O;
K = lsqcurvefit(rao_H2O,guess,C_TBA_H2O,rao_norm)
My error:
Error in Lab3_155 (line 17)
K = lsqcurvefit(rao_H2O,guess,C_TBA_H2O,rao_norm)
Caused by:
Failure in initial objective function evaluation. LSQCURVEFIT cannot continue.

Réponses (2)

Torsten
Torsten le 7 Mar 2019
Modifié(e) : Torsten le 7 Mar 2019
rao_H2O = @(k,x) k(1)*k(2)*C_TBA_H2O./(1+k(2)*C_TBA_H2O+(k(2)*C_H2O).^gamma(2))+k(3)*C_TBA_H2O;
xdata = zeros(size(rao_norm));
ydata = rao_norm;
K = lsqcurvefit(rao_H2O,guess,xdata,ydata);
Even
xdata = [];
might work, but I'm not 100% sure.
Best wishes
Torsten.

2 commentaires

No because you overwrote my "xdata" to be array of zeros which is weird.
Since you don't use "xdata" in the definition of "rao_H2O", the array is not necessary for your fitting task.

Connectez-vous pour commenter.

I figured out my issue. It was the lack of use of periods when multiplying or dividing arrays.

Catégories

En savoir plus sur Function Creation dans Centre d'aide et File Exchange

Commenté :

le 11 Mar 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by