convert number to string problem

5 vues (au cours des 30 derniers jours)
Yu Li
Yu Li le 10 Mar 2019
Commenté : Yu Li le 10 Mar 2019
I have a column number, and I want to add some string in front of it, and assign it to items of a drop-down list in an App.
take the test value test=1:1:5 for example, below is my code:
test=1:1:5;
for i=1:1:length(test)
tmp_name{i}=strcat('Data Set',num2str(test(i)));
end
to improve this code without the for-loop, I found that there is a function 'num2cell' but it does not work in this case:
test=1:1:5;
strcat('CVG Set',num2cell(test))
below is the result:
Capture.JPG
the numbers are converted to a rectangle symbol instead of string.
is there any mistake with my operation?
Bests,
Yu

Réponse acceptée

madhan ravi
madhan ravi le 10 Mar 2019
sprintfc('Data Set %d',test) % beware undocumented
  2 commentaires
madhan ravi
madhan ravi le 10 Mar 2019
Alternative:
cellstr("Data set "+test)
Yu Li
Yu Li le 10 Mar 2019
Thank you.
Bests,
Yu

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Plus de réponses (2)

Geoff Hayes
Geoff Hayes le 10 Mar 2019
Yu - I think the problem might be because when you use num2cell, you are creating a cell array of numbers and not a cell array of strings.
An alternative to what you have written is to use arrayfun where we apply a function to each of our integers (in test). For example,
tmp_name = arrayfun(@(x)sprintf('CVG Set %d',x),1:5, 'UniformOutput', false);
initializes the variable to
tmp_name =
'CVG Set 1' 'CVG Set 2' 'CVG Set 3' 'CVG Set 4' 'CVG Set 5'
which may be sufficient for what you need. You can modify the string in the sprintf call to get a different format (if that is what you need).
  1 commentaire
Yu Li
Yu Li le 10 Mar 2019
Thank you.
Bests,
Yu

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Image Analyst
Image Analyst le 10 Mar 2019
Yu:
Try this:
test = 1 : 5;
for k = 1 : length(test)
popupStrings{k} = sprintf('Data Set %d', test(k));
end
celldisp(popupStrings)
% Now load the strings into the popup (drop down list)
handles.popup1.String = popupStrings;
  2 commentaires
madhan ravi
madhan ravi le 10 Mar 2019
OP tries to avoid a for-loop.
Yu Li
Yu Li le 10 Mar 2019
Thank you.
Bests,
Yu

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