Is there a way to use regexprep() but skip the first occurrence of a space?
mystring = 'this is my string';
desired return:
mystring2 = 'this ismystring';

 Réponse acceptée

Akira Agata
Akira Agata le 13 Mar 2019

0 votes

How about using regexp to find the position of spaces, and delete 2nd~Nth spaces? Like:
mystring = 'this is my string';
pos = regexp(mystring,'\s');
mystring(pos(2:end)) = [];

Plus de réponses (1)

newbie9
newbie9 le 13 Mar 2019
Modifié(e) : newbie9 le 13 Mar 2019

0 votes

this works but perhaps is not most efficient:
[spaces,letters] = regexp(mystring, ' ', 'match', 'split', 'forceCellOutput');
spaces = [spaces{:}];
letters = [letters{:}];
mystring2 = [sprintf('%s',letters{2:end-1}), letters{end}];
mystring2 = strcat(char(letters(1)), {' '}, mystring2)

Catégories

En savoir plus sur Characters and Strings dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by