vv=(1:100)'
A=[3;8;21;44;60;79;99]
f_vv=find(vv==A);
vv(reshape(f_vv,length(f_vv),1))=[];
I got this error
Dimensions of arrays being concatenated are not consistent.

 Réponse acceptée

madhan ravi
madhan ravi le 14 Mar 2019
Modifié(e) : madhan ravi le 14 Mar 2019

0 votes

21;44
% ^
vv(ismember(vv,A))=[]

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