Finite Elements Method creating global stiffness matrix
23 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi everyone, I am really stuck in creating a code that creates global stiffness matrix that changing local stiffness matrixes value in every cycle.
For example it has to be
k1 -k1 0 0
-k1 k1+k2 - k2 0
0 - k2 k2+k3 -k3
0 0 -k3 k3
but my code doesn't change k1 to k2 for next step ... it only calculates for k1.
k1 -k1 0 0
-k1 k1+k1 - k1 0
0 - k1 k1+k1 -k1
0 0 -k1 k1
Please help me to solve this problem. Thanks.
clear
tp=[1 2]
for i=2:4
tp(i,:)=tp(i-1,:)+1
end
tpmax=max(max(tp));
KG=zeros(tpmax,tpmax);
for i=1:4
d(i)=32+(28/1200)*(2*i-1)*50
G(i)=(77000*pi*d(i).^4)/3200
k=[G(i) -G(i);-G(i) G(i)]
end
for n=1:4
i=n+[0 1]
j=i
KG(i,j)=KG(i,j)+k
end
2 commentaires
Mehmet Ali kurt
le 27 Avr 2020
Hi Omer ; If you have solition of 'Derived stiffness matrix for 1D 3-Nodes elements' can you send me please ?
Réponse acceptée
Stephan
le 15 Mar 2019
Modifié(e) : Stephan
le 15 Mar 2019
Hi,
you overwrite k every time. Im sure it could be done much easier - but here s a quick solution without any code optimization (Matlab users usually try to avoid for loops...):
clear
tp=[1 2];
for i=2:4
tp(i,:)=tp(i-1,:)+1;
end
tpmax=max(max(tp));
KG=zeros(tpmax,tpmax);
for i=1:4
d(i)=32+(28/1200)*(2*i-1)*50;
G(i)=(77000*pi*d(i).^4)/3200;
k(:,:,i)=[G(i) -G(i);-G(i) G(i)];
end
for n=1:4
i=n+[0 1];
j=i;
KG(i,j)=KG(i,j)+k(:,:,n);
end
Result is:
KG =
1.0e+08 *
0.9147 -0.9147 0 0 0
-0.9147 2.1154 -1.2006 0 0
0 -1.2006 2.7494 -1.5488 0
0 0 -1.5488 3.5165 -1.9677
0 0 0 -1.9677 1.9677
I think this is what you expected.
Best regards
Stephan
3 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!