For loop with decimal number matrix

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Abdulaziz Gheit
Abdulaziz Gheit le 16 Mar 2019
Commenté : Star Strider le 16 Mar 2019
Hi,
Any help with this for loop. I write a for loop and i tell it to increment by a small value, let's say 0.01. This loop is simple example of my issue. In my code I need to create big zeros soultion matrix to save my results into it.
if my loop increment is decimal number, how should I write the soultion matrix?
Thanks
NTUmax=10;
tt=100;
Soulution=zeros(tt,NTUmax);
for i=1:NTUmax %% Incrementing value should be e.g equal 0.1
NTU=(i);
dtempdt=NTU*2;
Soulution(:,i)=dtempdt;
end
  2 commentaires
madhan ravi
madhan ravi le 16 Mar 2019
Why do you need a loop? , the answer is simpler than a loop.
Abdulaziz Gheit
Abdulaziz Gheit le 16 Mar 2019
Hi madhan ravi,
This is just an example. I have a complicated numerical code and it's not as simple as this example.
Thank you very much for your attention

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Star Strider
Star Strider le 16 Mar 2019
I am not certain what you want to do.
If you want to use ‘i’ as a subscript, it must consist only of integers greater than 0.
This example creates ‘iv’ (your ‘i’ vector in 0.1 increments, the centre value in the ‘iv’ definition), then loops through it, defining ‘NTU’ in each iteration as an element of ‘iv’:
NTUmax=10;
tt=100;
Soulution=zeros(tt,NTUmax);
iv = 1:0.1:NTUmax; %% Incrementing value should be e.g equal 0.1
for i = 1:numel(iv)
NTU = iv(i);
dtempdt=NTU*2;
Soulution(:,i)=dtempdt;
end
Experiment to get the result you want.
  2 commentaires
Abdulaziz Gheit
Abdulaziz Gheit le 16 Mar 2019
Thank you very much Star strider. You've been a great help.
Star Strider
Star Strider le 16 Mar 2019
As always, my pleasure.

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