confusion related to 'for' loop.

epsilon = 2

p = cell(1,8);

for i = 1:8

p{i} = epsilon

end

How to edit this code so that I can get p{1} = epsilon,p{2} = epsilon ^2 ,p{2} = epsilon ^3 .......

i.e i want p{1} = 2,p{2} = 4, p{3} =8.....

Thanks

Answer 1

[madhan ravi]

p = num2cell(2.^(1:8))

[madhan ravi]

In your loop you just had to add

p{i} = epsilon^i

but you can straight away use the method in the answer.

Answer 2

[Steven Lord]

Do you need the elements in a cell array, or is having them in a regular vector sufficient?

epsilon = 2;
thepowers = 1:8;
p = epsilon.^thepowers

If you're preparing for epsilon being a vector or matrix in the future, you can still use this technique, taking advantage of implicit expansion which is a generalization of scalar expansion. It just gets a little more complicated for matrices or N-dimensional arrays.

epsilon = [1; 2; 3; 4];
thepowers = 1:8;
p2 = epsilon.^thepowers

For a matrix M, you want thepowers to be a 3-dimensional array.

epsilon = magic(4);
thepowers = reshape(1:8, 1, 1, []) % or
thepowers = reshape(1:8, [1 1 8])
p3 = epsilon.^thepowers