fitting 2 variable function to (x-1) form

1 vue (au cours des 30 derniers jours)
Benjamin
Benjamin le 28 Mar 2019
Commenté : Benjamin le 29 Mar 2019
I have this fit currently which works great:
fitobject = fit([r,eta/eta_c],H,ft,'problem',knownVals)
However, because of the nature of the data, it would make more sense if r was actually in the form of .
When I change the code to this:
fitobject = fit([(r-1),eta/eta_c],H,ft,'problem',knownVals)
My fit is completey messed up, and it looks nothing like the data.
My question is, am I employing the fit correctly?
The form should look like: Cij * (r-1)^i *(eta/eta_c)^j.
I wonder if I missed something in the fitting procedure?
  1 commentaire
Walter Roberson
Walter Roberson le 28 Mar 2019
Possibly it would help to use 'Upper' and 'Lower' (bounds) or 'StartPoint' options.

Connectez-vous pour commenter.

Réponse acceptée

Catalytic
Catalytic le 29 Mar 2019
Modifié(e) : Catalytic le 29 Mar 2019
My fit is completey messed up, and it looks nothing like the data.
It shouldn't look like the r and eta data, because that's not the data you fed to the fit, but it should look a lot like r-1 and eta/eta_c.
If I were you, I would just re-define all the r and eta data and forget about it instead of repeatedly having to remember to transform them everywhere they are used in the code. So, I would have
r=r-1;
eta=eta/eta_c;
fitobject = fit([r,eta],H,ft,'problem',knownVals);
plot(fitobject,[r,eta],z)
  1 commentaire
Benjamin
Benjamin le 29 Mar 2019
Thanks for catching that mistake!!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Get Started with Curve Fitting Toolbox dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by