code for horizontal projection profile of an image
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
hello friends, to perform skew detection and correction, iam using horizontal projection profile. so i need the code for horizontal projection profile to segment lines and i need the code for horizontal projection profile of each word, for image containing handwritten characters.
1 commentaire
Oleg Komarov
le 6 Août 2012
Please review these guidelines and ask a specific question: http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
Réponses (4)
Image Analyst
le 6 Août 2012
First pick an algorithm from section 23 of the Vision Bibliography: http://iris.usc.edu/Vision-Notes/bibliography/contents.html. Then come back here with your MATLAB coding questions.
0 commentaires
luong v
le 2 Déc 2015
Modifié(e) : luong v
le 2 Déc 2015
Hi every one, I have a license plate, now I want to use horizontal projection to segment the license plate into two lines. Please help me, Thanks you
1 commentaire
Image Analyst
le 2 Déc 2015
verticalProjection = mean(grayImage, 2);
horizontalProjection = mean(grayImage, 1);
Rujal
le 22 Jan 2016
how to plot horizontal projection horizontally ? I didn't get idea.
5 commentaires
Image Analyst
le 23 Jan 2016
But what if, in handwriting, descenders in one row dip below some risers in the row below? Those two rows would not be detected as two rows with any(). And with sum() and mean(), the descenders would get clipped. So to be really robust, you'd need something more sophisticated than these simple functions. But I can't spend the time to develop a robust OCR program for anyone.
Walter Roberson
le 23 Jan 2016
You need the ascenders and descenders for proper classification of the characters. Horizontal projection is simply not sufficient for the case where you do not have clean separation between the lines.
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!