Matrix dimension does not agree when using .*
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Sena Ece Uzungil
le 1 Avr 2019
Réponse apportée : Kelly Kearney
le 1 Avr 2019
Our code is calculating Taylor polynomials. We are sure that the problem is about P1 because program is plotting PO and f(x). We would really appreciate if anyone can solve our problem.
clc
clear all
close all
h = 0.01; % step size
X = -pi/8:h:7*pi/8; % domain
f=@(X) cot(X); % range
a=5*pi/8
Z1=@(X) diff(cot(X)) %first derivative
Z2=@(X) diff(cot(X),2) ; %second derivative
Z3=@(X) diff(cot(X),3) ; %third derivative
P0=@(X) f(a)*ones(size(X))
P1=@(X) f(a) + Z1(a).*(X-a);
P2=@(X) P1 + Z2(a) ./ factorial(2).*((X-a).^2);
P3=@(X) P2 + Z3(a) ./ factorial(3).*((X-a).^3);
xlim([0.1 3])
ylim([-2.5 2.5])
hold on
plot(X,f(X),'k','Linewidth',2)
plot(X,P0(X),'r','Linewidth',2)
plot(X,P1(X),'g-.','Linewidth',2)
plot(X,P2(X),'b--','Linewidth',2)
plot(X,P3(X),'m:','Linewidth',2)
The error we received:
Error using .*
Matrix dimensions must agree.
Error in Untitled>@(X)f(a)+Z1(a).*(X-a)
Error in Untitled (line 26)
plot(X,P1(X),'g-.','Linewidth',2)
0 commentaires
Réponse acceptée
Kelly Kearney
le 1 Avr 2019
When you calculate
Y = diff(X,n)
where X is a vector, Y will have length length(X)-n. So you need to adjust X accordingly when plotting, e.g.
plot(X,f(X),'k','Linewidth',2)
plot(X,P0(X),'r','Linewidth',2)
plot(X(1:end-1),P1(X),'g-.','Linewidth',2)
plot(X(1:end-2),P2(X),'b--','Linewidth',2)
plot(X(1:end-3),P3(X),'m:','Linewidth',2)
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!