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counting no .of temperature less than 32 in array

1 vue (au cours des 30 derniers jours)
Abhishek singh
Abhishek singh le 3 Avr 2019
Clôturé : madhan ravi le 30 Août 2020
function numfreeze = freezing(v)
count = 0;
i =v()
j = 32
if i < 32
count = count+1
numfreeze = count
else
end
  1 commentaire
Abhishek singh
Abhishek singh le 3 Avr 2019
geeting errror
i =
45 21 32 31 51 12
j =
32
Output argument "numfreeze" (and maybe others) not assigned during call to "freezing".

Réponses (6)

Ngei Katumo
Ngei Katumo le 22 Août 2019
function w = freezing (A)
w = sum (logical (A(A<32)));
end

madhan ravi
madhan ravi le 3 Avr 2019
v=[45 21 32 31 51 12];
threshold=32;
numfreeze = freezing(v,threshold) % function call
function numfreeze = freezing(v,threshold) % function definition
numfreeze = nnz(v<threshold);
end
  6 commentaires
Image Analyst
Image Analyst le 11 Juin 2019
You mean freezing.m, since that's what was asked.
madhan ravi
madhan ravi le 15 Sep 2019
Ah yes exactly:)

Nazneen Sayyad
Nazneen Sayyad le 10 Juin 2019
Write a function called freezing that takes a vector of numbers that correspond to daily low temperatures in Fahrenheit. Return numfreeze, the number of days with sub freezing temperatures (that is, lower than 32 F) without using loops. Here is an example run:
numfreeze = freezing([45 21 32 31 51 12])
numfreeze =
3
function numfreeze = freezing(A)
B=A(A<32);
numfreeze=numel(B);
end

Ajith Thomas
Ajith Thomas le 19 Juil 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
no_logical_values=lowerthan_32(lowerthan_32>=0);
numfreeze=length(no_logical_values);
end
  1 commentaire
Ajith Thomas
Ajith Thomas le 19 Juil 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
numfreeze=numel(lowerthan_32);
end

Roshan Singh
Roshan Singh le 15 Sep 2019
function numfreeze = freezing(x)
f = x(x<32);
numfreeze = length(f);
end

MADHURJYA DAS
MADHURJYA DAS le 30 Août 2020
function numfreeze=freezing(A)
x=(A<32);
numfreeze=sum(x(:));
end

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R2015b

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