ismember 0×0 empty logical array to logic
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Hi All,
I have an array "A = [1 2 3 4 5 6]" which its length reduces in a loop
if ~ismember(A,ID)
do this
else
do that
end
This works fine until the A=[], which ismember returns
0×0 empty logical array
However I need a Single Value and not logical array. Note that I cannot use any and all functions to reduce Logical Arrays to Single Value, beacuse I faced with other problems when "A" array is not yet empty!
How can I fix this problem?
1 commentaire
madhan ravi
le 19 Avr 2019
First and foremost what is your goal? What is the expected result for given A?
Réponse acceptée
Walter Roberson
le 19 Avr 2019
The obvious answer would seem to be to test
if isempty(A) || ~ismember(A,ID)
If you were hoping there were a hidden preference you could set that would make ismember(A,ID) return a non-empty value without having to change your test.. sorry, there is no such test.
I would point out that you could also rewrite your code:
if ismember(A,ID)
do that
else
do this
end
the ismember() would be empty when A is empty, so the test would fail, and do that would not be done, leaving you to fall through to the do this case.
1 commentaire
Plus de réponses (1)
the cyclist
le 19 Avr 2019
Modifié(e) : the cyclist
le 19 Avr 2019
Making a huge guess here, but are you sure you don't mean
~ismember(ID,A)
rather than
~ismember(A,ID)
Then, assuming ID is a scalar,
~ismember(ID,[])
returns true, which I'm guessing is the result you are intending.
Like I said ... just a guess. (And you might need to adjust your other logic accordingly.)
Part of the reason I am guessing this is that
~ismember(A,ID)
returns a vector of values (if A is a vector and ID is a scalar), which is not typically what you want in an if statement. But maybe it is in your case.
3 commentaires
the cyclist
le 19 Avr 2019
OK, so are you aware that
if [true true false]
do this
else
do that
end
will "do that", because every element has to be true to get to the "do this" part of the if statement. (The reason I am so insistent is that this is a very common misunderstanding, and people often think that MATLAB somehow process the vector "in parallel".)
It would be good to give a an example of a combination of A and ID where you expect your if statement to "do this". It seems to me that the only way it happens is if none of the elements of A is equal to ID, in which case there are simpler ways to do what you want.
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