Réponse acceptée

Geoff Hayes
Geoff Hayes le 20 Avr 2019

0 votes

sesha - the only difference between this and the usual sine curve is that it is "inverted". Try doing
x = -pi:0.01:pi;
y = -1 * sin(x);
plot(x,y);
and see how the -1 scalar gives you what you are looking for.

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