Adding new field to structure array

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Maciej Grybko
Maciej Grybko le 22 Avr 2019
Commenté : Maciej Grybko le 22 Avr 2019
I have a structure vector s with already existing fields f1 and f2. I want to perform calculations on those fields for every single element and save results to a new field f3. Can following expressions be simplified?
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2])
a = num2cell(a)
[s.f3] = a{:}

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Maciej Grybko
Maciej Grybko le 22 Avr 2019
Modifié(e) : Maciej Grybko le 22 Avr 2019
Okay, I figured it out:
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2], 'UniformOutput',false)
[s.f3] = a{:}
But still, is there any way to combine 2nd and 3rd line?
  1 commentaire
madhan ravi
madhan ravi le 22 Avr 2019
Isn’t that what Alex posted 30 minutes earlier to this?

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Walter Roberson
Walter Roberson le 22 Avr 2019
Modifié(e) : Walter Roberson le 22 Avr 2019
Not really. You could reduce by one line by using
a = num2cell(arrayfun(fun, [s.f1], [s.f2]));
for whatever that is worth.
You could go through struct2cell() and create a new cell with the result, but it is not going to be any simpler than what you already have.
You could do it in fewer lines using especially obscure syntax. I am the only person whom I have seen use that syntax in about a decade -- I posted an example a few months ago just to prove that it could be done -- and that it was not worth doing. It would not be any simpler: it would leave even fairly advanced MATLAB users scratching their heads and wondering, "Can you do that???"
  6 commentaires
madhan ravi
madhan ravi le 22 Avr 2019
;) knew it , thank you sir Walter.
Maciej Grybko
Maciej Grybko le 22 Avr 2019
Thanks

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