Row index exceeds matrix dimensions

4 vues (au cours des 30 derniers jours)
Peter Larsen
Peter Larsen le 24 Avr 2019
Commenté : Peter Larsen le 24 Avr 2019
Hi
I have a 143x4 matrix, which looks like this
A=[ 1 556037.025 6237642.046 5.964;
1 556037.035 6237642.041 5.960;
1 556037.028 623742.041 5.967;
2 556032.654 623730.067 10.368;
2 556032.652 623730.060 10. 364;
4 556042.000 623730.000 5.000;
4 556042.002 623730.005 5.010] ;
Column 1 is the point number, column 2-4 are X,Y,Z coordinates.
Each point is measured between 1 and 5 times.
My code is:
A=load('Test.txt');
A=sortrows(A);
T=array2table(A);
m=varfun(@mean,T,'GroupingVariables',1);
out=A;
out(:,2:end)=out(:,2:end) - m{A(:,1),3:end}
I get the error Row index exceeds table dimensions
I have tried to test different scenarios and the error occurs when a point is missing, for example if there is no point number 7, so the first column goes from 6 to 8.
Any idea what is wrong?
  4 commentaires
Peter Larsen
Peter Larsen le 24 Avr 2019
The complete code is updated now
Peter Larsen
Peter Larsen le 24 Avr 2019
Hi
It works until the numbers in column 1 skips a number (See updated revision). If the point number skips from 2 to 4 without having a point number 3, the error occurs

Connectez-vous pour commenter.

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 24 Avr 2019
T = array2table(A);
m = varfun(@mean,T,'GroupingVariables',1);
out = A;
[~,~,ii] = unique(A(:,1));
out(:,2:end) = out(:,2:end) - m{ii,3:end};

Plus de réponses (0)

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits


Version

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by