Finding row numbers of a matrix where certain column entries match a criterion

I have a 64x3 matrix C0 as below. I would like to look at row 63=[4 4 3], and for each j=1:3, find the row numbers of C0 such that the not-j's column entries in that row equals the corresponding values in row 63. e.g. for j=1, find all rows of C0 such that the 2nd and 3rd values are [4 3]. (but would like a succinct way of writing this in a loop for all j)

Thanks for your help!

    C0=[];
    for R1=1:4
        for  R2=1:4
             for R3=1:4
                C0=[C0; [R1 R2 R3]];
             end
        end
    end

Answer 1

[Walter Roberson]

find(C0(:,2) == 4 & C0(:,3) == 3)

[wy6622]

Thanks for answering! I'd like to loop this over j (so for j=2 it'd be find(C0(:,1) == 4 & C0(:,3) == 3, etc., and would like to find a succinct way of writing this, as I'll need to apply this to other matrices of bigger sizes. Thank you!

[Walter Roberson]

RowOfInterest = C0(64,:);
nc = size(C0,2);
vec = 1 : nc;
results = cell(nc,1);
mask = C0 == RowOfInterest;
for j = 1 : nc
    nonj = vec; nonj(j) = [];
    results{j} = find( all(mask(:,nonj), 2 ) );
end

The detection of matching rows could probably be vectorized (at the cost of temporary memory), but find() is difficult to vectorize.

[wy6622]

I see. Thank you!