Logicals with empty double column vectors

Hi

I have got this code:

a=Pf_ID;                             %--> 5x1cell
b=magic(5);
c=find(cellfun(@isempty,a));        %--> creates a double row vector with two entries as 2 elements in Pf_ID as empty
b(:,c)=[];
a(c,:)=[];

cc=find(cellfun(@isempty,a));
ccc=double.empty(0,1);
if cc==ccc                            % -->QUESTION: I cannot manage that this if statement becomes 'true' so that a=88. Do you have any hints?
    a=88
end

[Jan]

The question is not clear:

I cannot manage that this if statement becomes 'true' so that a=88.

What do you get? What do you want instead? What exactly does "double.empty(0,1)"? Maybe you mean:

if isempty(cc)
    a = 88;
end

Answer 1

[Guillaume]

c=find(cellfun(@isempty,a));
a(c,:)=[];

The second line implies that a is 2D. Yet, find as used will return linear indices, so if a is indeed 2D the second line will error with 'index exceeds array dimension' if any element in column 2 or later is empty. You haven't explained what this code is meant to do but probably doesn't do what you want. It certainly doesn't do it safely.

You also haven't explained what your 2nd bit of code is meant to do. If you want to test that cc is empty, you use the exact same isempty test you've been using:

cc = find(cellfun(@isempty, a))
if isempty(cc)
    a = 88;
end

Or you don't bother with the find, and just check that there's no true value returned by your cellfun:

if ~any(cellfun(@isempty, a))
    a = 88;
end

[Jan]

As usual I mention, that cellfun('isempty', C) is more efficient than cellfun(@isempty, C).