How can I create a random array like the example below?

A=[1 1 2 2 7 7 9 9]

B=[3 5 6 8 10 11] : randomly choose all items from B and input between 2 same number of A

between same bumber can be no number

for example : C=[1 8 6 1 2 5 3 2 7 11 7 9 10 9]

or C=[1 1 2 5 3 8 2 7 11 6 7 9 10 9]

or C=[1 1 2 5 8 3 2 7 11 6 10 7 9 9]

I asked from another question for help and recieved the below code. But it is not flexible for position of non-number

A=[1 1 2 2 7 7 9 9];
B=[3 5 6 8 10 11];
Na = numel(A);
Nb = numel(B);
Xb = randperm(Nb); % to shuffle the order of B.

if Nb<=Na/2 % "if don't have enough B to fill in"
	Xa = zeros(1,Na/2);
	Xa(randperm(Na/2,Nb))=1 % the number of elements of B to pick.
    
else
	Xa = randperm(Nb,Na/2-1)
	Xa = diff([0,sort(Xa),Nb]) % the number of elements of B to pick.
end

T = [num2cell(A(1:2:Na));mat2cell(B(Xb),1,Xa);num2cell(A(2:2:Na))];
C = [T{:}]

[Jan]

And here is the link to the other thread: https://www.mathworks.com/matlabcentral/answers/458404-how-can-i-create-a-random-array-like-the-example-c

Answer 1

[Jan]

A = [1 1 2 2 7 7 9 9];
B = [3 5 6 8 10 11];

nA = numel(A);
nB = numel(B);

rB = B(randperm(nB, nB)).';
iA = randi([1, nA/2], nB, 1);  % Each value of B gets a bin in A
C  = accumarray(iA, rB, [nA/2, 1], @(x) {x});

AC = num2cell(A(1:2:nA).');    % same as for A(2:2:nA)
T  = [AC, C, AC].';
Result = vertcat(T{:}).'

[Hang Vu]

It is exactly what I want, Thank you so much for the help!