Recursive symbolic differentiation with anonymous functions

3 vues (au cours des 30 derniers jours)
Leo Simon
Leo Simon le 13 Août 2012
This is closely related to an earlier post of mine, but i thought I should make it a separate thread, since it's not really the same topic
I'd like the commands
syms x lambda
f = @(x)B(x);
g = @(x)lambda*C(x);
h = @(x)f(x) - g(x);
diff(h,x)
to "go inside of h(x)" and differentiate both f and g, to return
diff(B(x), x) - lambda*diff(C(x), x)
Instead it returns
diff(f(x), x) - diff(g(x), x)
I get the answer I want if I use
syms x
f = sym('B(x)')
g = sym('lambda*C(x)')
h = f - g; diff(h,x)
but this coding is less flexible than the former, since the argument 'x' is "hard-coded" into my functions, so I would have to use subs everytime I want to give my functions different arguments.
So in short, what I'm hoping for is the best of both worlds, the flexibility provided by anonymous functions plus the recursive (and other) properties provided when I use "sym"
  1 commentaire
Oleg Komarov
Oleg Komarov le 13 Août 2012
Modifié(e) : Oleg Komarov le 13 Août 2012
I don't see the problem, the subs() in a symbolic context it's just a line of code.

Connectez-vous pour commenter.

Réponses (1)

Walter Roberson
Walter Roberson le 13 Août 2012
diff() cannot be applied to function handles.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by