Sorting 2D matrix and retaining nodes in triangle groups
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Fredrik P
le 30 Avr 2019
Réponse apportée : Fredrik P
le 2 Avr 2020
I am trying to optimize a script (below) that finds the bounding boxes to functional values of all lower left triangles in a 2D space. The code goes through all the triangles and then sorts the nodes in ascending order based on the functional values. This seems inefficient.
Is there some way that I could sort the functional values before the loops but still retain the nodes in the triangle groups? Or some other smart way to speed things up?
clear;
x = (1:600)';
y = (1:500);
z = 2 * x.^2 + y;
zGrid = linspace(min(z, [], 'all') - 1, max(z, [], 'all') + 1, 200);
for iX = 1:length(x) - 1
for iY = 1:length(y) - 1
% Node indices
xIndices = [iX, iX, iX + 1];
yIndices = [iY, iY + 1, iY];
% Node values
xTmp = x(xIndices);
yTmp = y(yIndices);
zTmp = z(sub2ind(size(z), xIndices, yIndices));
% Node sorted according to z
[zSorted, indicesSorted] = sort(zTmp);
xSorted = xTmp(indicesSorted);
ySorted = yTmp(indicesSorted);
% Get bounding box on zGrid
iMin = find(zGrid <= zSorted(1), 1, 'last');
iMax = find(zGrid(iMin:end) >= zSorted(end), 1, 'first') + (iMin - 1);
end
end
0 commentaires
Réponse acceptée
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Shifting and Sorting Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!