function main
Pr=1; L=-1;D=1;
R=0.1;Sc=1;
% D=input('D='); %%D=0.5, 1, 1.5
xa=0;xb=6;
solinit=bvpinit(linspace(xa,xb,101),[0 1 0 1 0 1 0]);
sol=bvp4c(@ode,@bc,solinit);
xint=linspace(xa,xb,101);
sxint=deval(sol,xint);
figure(1)
plot(xint,sxint(2,:));
xlabel('\eta');
ylabel('f^\prime');
hold on
function res=bc(ya,yb)
res=[ya(1); ya(2)-L-D*ya(3); ya(4)-1; ya(7)-1; yb(2)-1; yb(4);yb(6)];
end
function dydx=ode(x,y)
dydx=[y(2); y(3); y(2)^2-y(3)*y(1)-1; y(5); -3*Pr*y(1)*y(5)/(3+4*R); y(7); -Sc*y(1)*y(7)];
end
end
Actually I dont know the concept of DUAL solution.

 Réponse acceptée

Stephan
Stephan le 30 Avr 2019
Modifié(e) : Stephan le 30 Avr 2019

0 votes

Hi,
maybe this is useful:
As shown in the link, the results strongly depend on the initial guesses - here is an example:
[sol1, sol2] = main
function [sol1, sol2] = main
Pr=1;
L=-1;
D=[0.5, 1, 1.5];
R=0.1;
Sc=1;
for k = 1:numel(D)
xa=0;xb=6;
solinit1=bvpinit(linspace(xa,xb,101),[0 1 0 1 0 1 0]);
solinit2=bvpinit(linspace(xa,xb,101),[-1 -1 -1 -1 -1 -1 0]);
sol1=bvp4c(@ode,@bc,solinit1);
sol2=bvp4c(@ode,@bc,solinit2);
figure(1)
plot(sol1.x,sol1.yp(1,:),'-r')
xlabel('\eta');
ylabel('f^\prime');
hold on
plot(sol2.x,sol2.yp(1,:),'-b')
end
hold off
function res=bc(ya,yb)
res=[ya(1); ya(2)-L-D(k)*ya(3); ya(4)-1; ya(7)-1; yb(2)-1; yb(4);yb(6)];
end
function dydx=ode(x,y)
dydx=[y(2); y(3); y(2)^2-y(3)*y(1)-1; y(5); -3*Pr*y(1)*y(5)/(3+4*R); y(7); -Sc*y(1)*y(7)];
end
end
results in:
dual.JPG
Best regards
Stephan

5 commentaires

MINATI
MINATI le 30 Avr 2019
Modifié(e) : MINATI le 30 Avr 2019
@ Stephan
How to know the initial guesses.
Actually if we add some EXTRA parameters, previous guesses may not work.
OR if we change
solinit2=bvpinit(linspace(xa,xb,101),[0 1 0 1 0 1 0]); solution is different.
Also that guess doesn't work for other figures.
So what is the trick for new guesses?
Stephan
Stephan le 30 Avr 2019
I would love to tell you, but i can not, because i have no in Sicht to your problem.
madhan ravi
madhan ravi le 1 Mai 2019
Sicht => insight
MINATI
MINATI le 1 Mai 2019
OK Stephan
Thanks
MINATI
MINATI le 15 Mai 2019
Following a Very bad CYCLONE in our State, I didnt follow your code properly as we had no electricity, no internet.
Thats why came late to the forum.
You had considered
f=y(1,:), f'=yp(1,:)
What is f"
Is it yp(2,:), If yes not matching. And
I have taken
f=y(1), f'=y(2); f"= y(3);
Theta= y(4), Theta'=y(5);
phi=y(6);phi'=y(7)

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Mathematics dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by