matlab negative and positive infinity problem

hi there,

I am quite confused about how matlab deals with inf and -inf. Here is the problem I confronted

x0p = 0;
b = 0.0050;
y0p =0;
(x0p-b)/y0p

ans =

   Inf

But it should be -inf. I changed the value of b but still got the same answer. I tried using numbers directly and it seems correct as shown below. I don't know the mechanism behind it. So I hope someone could help me figure it out.

   -1/0

ans =

  -Inf

Cheers,

Jianan

[madhan ravi]

sprintf('%.32f',x0p) % what does it result to?

I get -Inf btw.

[Walter Roberson]

-Inf is what shows up for me in R2019a. Which version are you using, on which operating system?

I suggest you use num2hex(x0p) and y0p to verify that they are true zeros. Also, store the result in a variable and use num2hex() on it. -inf is fff followed by all 0, and +inf is 7ff followed by all 0.

[Jianan He]

Thanks guys, I found my problem. I didn't realize that zero can be negative or positive in matlab.

sprintf('%.32f',y0p)

ans =

    '-0.00000000000000000000000000000000'

Thanks again, it's my first time asking questions in community and I appreciate your guys help!