matrix insert with a condition

1 vue (au cours des 30 derniers jours)
JK
JK le 17 Mai 2019
Commenté : Guillaume le 18 Mai 2019
can you help me insert m x n matrix into M x N matrix with a condition that is without zero.
starting location is (x,y)
M x N =
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
m x n =
0 2 2 0
2 2 2 2
0 2 2 0
(x,y) = (4,3)
M x N =
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 2 2 1 1 1 1
1 1 1 2 2 2 2 1 1 1
1 1 1 1 2 2 1 1 1 1

Réponse acceptée

Guillaume
Guillaume le 17 Mai 2019
A = [1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1];
B = [0 2 2 0
2 2 2 2
0 2 2 0];
row = 3; col = 4;
toinsert = B + ~B .* A(row:row+size(B, 1)-1, col:col+size(B, 2)-1);
A(row:row+size(B, 1)-1, col:col+size(B, 2)-1) = toinsert
  2 commentaires
JK
JK le 17 Mai 2019
thanks for your feedback.
I am looking for a solution with a larger matrix which unfortunately i can't do all the individual calculations.
Guillaume
Guillaume le 18 Mai 2019
What individual calculations?
The code above is completely generic and will work for any size A and B and wherever any zeros are in B.
If it doesn't work for your generic case, then you need to explain a lot better what it is you want.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by