remove cell array content matrix with condition: length of element in cell smaller than specific value

1 vue (au cours des 30 derniers jours)
Let's say:
cell_A : 1x3 cell class
cell_A={matrix_1 matrix_2 matrix_3 }
cell_A={[5x3 double] [1x3 double] [6x3 double]}={[1 1 1;2 2 2;3 3 3;4 4 4;5 5 5] [11 11 11] [0 0 0;1 1 1;2 2 2;3 3 3;4 4 4;5 5 5]}
matrix_1 [1 1 1;2 2 2;3 3 3;4 4 4;5 5 5] %5-by-3 matrix
matrix_2 [11 11 11] %1-by-3 matrix
matrix_3 [0 0 0;1 1 1;2 2 2;3 3 3;4 4 4;5 5 5] %6-by-3 matrix
If I wanna count how many row of each matrix in cell A, the result is:
ans=[ 5; 1 ;6];
Now, I wanna delete matrix of cell A, If the number row in matrix <2. How can I do that? The result is:
result : 1x2 cell class
result={matrix_1 ; matrix_3 }
result={[5x3 double] [6x3 double]}={[1 1 1;2 2 2;3 3 3;4 4 4;5 5 5] [0 0 0;1 1 1;2 2 2;3 3 3;4 4 4;5 5 5]}

Réponse acceptée

Alex Mcaulley
Alex Mcaulley le 21 Mai 2019
cell_A = {[1 1 1;2 2 2;3 3 3;4 4 4;5 5 5];[11 11 11];[0 0 0;1 1 1;2 2 2;3 3 3;4 4 4;5 5 5]};
cell_A(cellfun(@size,cell_A,repmat({1},size(cell_A))) < 2) = [];
  2 commentaires
Stephen23
Stephen23 le 21 Mai 2019
Modifié(e) : Stephen23 le 21 Mai 2019
Using cellfun's backwards-compatibility syntax makes this simpler (two lines for clarity):
idx = cellfun('size',A,1)<2;
A(idx) = []
Alex Mcaulley
Alex Mcaulley le 21 Mai 2019
Thanks Stephen. I had never seen the backwards-compatibility before.

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