Calculation between 2 vectors where one is 4d and other is 1d
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Dear,
I have 2 vectors. One is of 4d form and other is of 1d form. The value of one vector will be subtracted from the values of the othe vector.
Example:
A=[val(:,:,1,1)
= 0.67
val(:,:,2,1)
=0.55
val(:,:,3,1)
=0.12
val(:,:,1,2)
= 0.12
val(:,:,2,2)
=0.50
val(:,:,3,2)
=0.11
]
B=[1
0]
The operation would be like this one
Result=[
val(:,:,1,1) =0.67-1
val(:,:,2,1) =0.55-1
val(:,:,3,1) =0.12-1
val(:,:,1,2) =0.12-0
val(:,:,2,2) =0.5-0
val(:,:,3,2) =0.11-0
]
Would you please help me calculating this?
thanks,
0 commentaires
Réponses (1)
Raghunandan V
le 28 Mai 2019
Modifié(e) : Raghunandan V
le 28 Mai 2019
Hi,
small explanation of How I approached the answer. I changed domenstion on B so that it would that of A and the subtracted them both
A = zeros(5,5, 3,2) ;%assumed Dimensions
%value storing
A(:,:,1,1)= 0.67;
A(:,:,2,1)= 0.55;
A(:,:,3,1)= 0.12;
A(:,:,1,2)= 0.12;
A(:,:,2,2)= 0.5;
A(:,:,3,2)= 0.11;
B = [1 ;0];
%get dimenstions of A
[m n o p ] = size(A);
%create two temporary matrices
R1 = B(1)*ones(m,n,o);
R2 = B(2)*ones(m,n,o);
%here multiplication is used to make it versatile for any value of B
%initialize new B
NewB = zeros(m,n,o,p);
NewB(:,:,:,1)= R1;
NewB(:,:,:,2)= R2;
result = A - NewB;
Voir également
Catégories
En savoir plus sur Subplots dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!