Please anyone help me with the error!

3 vues (au cours des 30 derniers jours)
Gaurav Srivastava
Gaurav Srivastava le 28 Mai 2019
Commenté : KSSV le 28 Mai 2019
Please write the code-Screenshot (14).png

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madhan ravi
madhan ravi le 28 Mai 2019
fprintf('The potential difference is \n')
disp(potential)

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KSSV
KSSV le 28 Mai 2019
potential = double(potential) ;
fprintf('the potential difference is = %f\n',potential) ;
Your variable potential is in syms...convert it to double. Read about double.
  3 commentaires
Gaurav Srivastava
Gaurav Srivastava le 28 Mai 2019
Still not working sir!Screenshot (15).png
KSSV
KSSV le 28 Mai 2019
You should not attach code as image.......copy the code here.

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