How to Permute the array with specific number?

3 vues (au cours des 30 derniers jours)
Hang Vu
Hang Vu le 28 Mai 2019
Commenté : Hang Vu le 29 Mai 2019
I want to keep 1,2,6,7,9,10, they will not move
I have this array
b=[1,5,2,8,6,11,7,9,3,10]
P=perms(b);
HOw to use perms for 3,5,8,11 among 6 numbers above?

Réponse acceptée

Stephen23
Stephen23 le 29 Mai 2019
>> b = [1,5,2,8,6,11,7,9,3,10];
>> idx = ~ismember(b,[1,2,6,7,9,10]);
>> mat = repmat(b,factorial(nnz(idx)),1);
>> mat(:,idx) = perms(b(idx))
mat =
1 11 2 8 6 5 7 9 3 10
1 11 2 8 6 3 7 9 5 10
1 11 2 5 6 8 7 9 3 10
1 11 2 5 6 3 7 9 8 10
1 11 2 3 6 8 7 9 5 10
1 11 2 3 6 5 7 9 8 10
1 8 2 11 6 5 7 9 3 10
1 8 2 11 6 3 7 9 5 10
1 8 2 5 6 11 7 9 3 10
1 8 2 5 6 3 7 9 11 10
1 8 2 3 6 11 7 9 5 10
1 8 2 3 6 5 7 9 11 10
1 5 2 11 6 8 7 9 3 10
1 5 2 11 6 3 7 9 8 10
1 5 2 8 6 11 7 9 3 10
1 5 2 8 6 3 7 9 11 10
1 5 2 3 6 11 7 9 8 10
1 5 2 3 6 8 7 9 11 10
1 3 2 11 6 8 7 9 5 10
1 3 2 11 6 5 7 9 8 10
1 3 2 8 6 11 7 9 5 10
1 3 2 8 6 5 7 9 11 10
1 3 2 5 6 11 7 9 8 10
1 3 2 5 6 8 7 9 11 10
  6 commentaires
Stephen23
Stephen23 le 29 Mai 2019
Modifié(e) : Stephen23 le 29 Mai 2019
Here is a simple but not-very-efficient solution (warning: generates all permutations and discards invalid ones) (note that 1 and 10 have been ignored to make the code simpler):
b = [5,2,8,6,11,7,9,3];
V = [2,6,7,9]; % fixed
P = perms(b);
[X,Y] = ismember(P.',V);
R = reshape(Y(X),[],size(P,1));
D = all(diff(R,1,1)>0);
Z = P(D,:)
Giving:
Z =
3 11 8 2 6 7 9 5
3 11 8 2 6 7 5 9
3 11 8 2 6 5 7 9
3 11 8 2 5 6 7 9
3 11 8 5 2 6 7 9
3 11 2 6 8 7 9 5
3 11 2 6 8 7 5 9
3 11 2 6 8 5 7 9
3 11 2 6 7 8 9 5
... lots of lines here
5 3 2 11 6 7 8 9
5 3 2 11 6 7 9 8
5 3 2 11 8 6 7 9
5 3 2 6 11 8 7 9
5 3 2 6 11 7 8 9
5 3 2 6 11 7 9 8
5 3 2 6 8 11 7 9
5 3 2 6 8 7 11 9
5 3 2 6 8 7 9 11
5 3 2 6 7 8 11 9
5 3 2 6 7 8 9 11
5 3 2 6 7 11 8 9
5 3 2 6 7 11 9 8
5 3 2 6 7 9 11 8
5 3 2 6 7 9 8 11
5 3 2 8 6 11 7 9
5 3 2 8 6 7 11 9
5 3 2 8 6 7 9 11
5 3 2 8 11 6 7 9
Hang Vu
Hang Vu le 29 Mai 2019
Thank you so much! this is what I want!

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Plus de réponses (1)

Jan
Jan le 28 Mai 2019
Modifié(e) : Jan le 28 Mai 2019
You did not mention how the output should look like. Perhaps:
b = [1,5,2,8,6,11,7,9,3,10];
keep = [1,2,6,7,9,10];
move = ~ismember(b, keep);
P = perms(b(move));
R = repmat(b, size(P,1), 1);
R(:, move) = P
  6 commentaires
Jan
Jan le 29 Mai 2019
@Hang Vu: I do not understand, what you mean. You solved the problem, but this is another one? Is the problem of your question solved or not?
"if the moving numbers move then you will see the keeping move..." - what does this mean?
Please explain exactly, what you want to achieve.
Hang Vu
Hang Vu le 29 Mai 2019
I am sorry, I miss-understood. I want to list all possible array of the moving numbers between the keeping one

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