Coding infinite many series ?

12 vues (au cours des 30 derniers jours)
Arzu Ahmadova
Arzu Ahmadova le 28 Mai 2019
Commenté : Walter Roberson le 1 Juin 2019
clc
close all
alpha=1/2;
beta=1/3;
T=1;
t=0:T;
a=2; %x1^0
b=1; %x2^0
a11=1;
a12=2;
a21=3;
a22=4;
for (k=0:'k<K':k++)
l=2*k+2;
A=zeros(:,l);
for (j=1: j<J; j++)
x=0;y=0;p=0;q=0;
for (i=0: i<k: i++)
x=x+alpha*A[2*i+1]+ beta*A[2*i];
y=y+alpha*A[2*i+1]+ beta*A[2*i+2]};
p=p+(a11^sum_odd[A]*a22^sum_even[A]*t^(x+k*(alpha+beta)))/gamma(x+k*(alpha+beta)+1);
q=q+(a11^sum_odd[A]*a22^sum_even[A]*t^(y+(k+1)*(alpha+beta)+k*beta)))/gamma(y+(k+1)*(alpha+beta)+k*beta+1);
for n=1; n<=l; n++
A[n]=j
function f=mydouble(sum_odd[A]+sum_even[A])
f.value=A;
end
function update(A)
end
x1(t)=a*a12^k.*a21^k.*p+b*a12^(k+1).*a21^k*q;
end
end
end
end
  1 commentaire
Walter Roberson
Walter Roberson le 1 Juin 2019
Your for loops have the wrong syntax.
Note: MATLAB does not have any ++ operator either.

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