Effacer les filtres
Effacer les filtres

Multiply Image Pixels by a Matrix

9 vues (au cours des 30 derniers jours)
Royi Avital
Royi Avital le 22 Août 2012
Hello, Let's say I have a 3 channel image M -> [numRowx * numColumns * numChannels]. I also have a 3 by 3 matrix A (Color Conbersion).
I would like to multiply each pixel 3 channel by the matrix to have a new 3 channels pixel.
How would you do that the most efficient way without writing the actual formula by hand (Multiplying each channel of the image by a row)?
My best so far is:
rgbToYPbPrMat = [0.299, 0.587, 0.144; 0.5, -0.419, -0.081; -0.169, -0.331, 0.5];
yPbPrToRgbMat = inv(rgbToYPbPrMat);
inputImage = randi([0, 255], [256, 256, 3], 'uint8');
inputImageFP = double(inputImage) / 255; %<! Floating Point
figure;
image(inputImage);
axis image;
inputImageYPbPrFP = shiftdim(reshape((rgbToYPbPrMat * reshape(shiftdim(inputImageFP, 2), [3, (256 * 256)])), [3, 256, 256]), 1);
Thanks.
  3 commentaires
Royi Avital
Royi Avital le 22 Août 2012
Hi @Sean, Look at my code I added.
I couldn't make it work with 'bsxfun'.
Royi Avital
Royi Avital le 23 Août 2012
Anyone? Please...

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Jan
Jan le 23 Août 2012
I cannot check it currently, but please try:
M = rand(numRows, numColumns, 3);
T = rand(3, 3);
P = reshape(M, numRows * numColumns, 3) * T';
Result = reshape(P, numRows, numColumns, 3);
  1 commentaire
Royi Avital
Royi Avital le 23 Août 2012
Hi, Checked it, it does work and it the fastest so far (Since the Transpose works on the smaller matrix).
Do you think there's even a faster way?
Thanks.

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