Given a matrix "A", how to create a row vector of 1s that has the same number of elements as "A" has rows?
271 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Gaurav Srivastava
le 4 Juin 2019
Modifié(e) : MathWorks Support Team
le 21 Oct 2024
Given a matrix "A", do the following things:
- Create a row vector of 1's that has the same number of elements as "A" has rows.
- Create a column vector of 1's that has the same number of elements as "A" has columns.
- Using matrix multiplication, assign the product of the row vector, the matrix "A", and the column vector (in this order) to the variable "result".
A = [1:5; 6:10; 11:15; 16:20];
Réponse acceptée
Manali Gupta
le 21 Oct 2024
Modifié(e) : MathWorks Support Team
le 21 Oct 2024
Given a matrix "A", you can find the number of rows of A by using "size(A,1)". You can find the number of columns of "A" by using "size(A,2)". You can then use "ones" to create a row or column vector of 1's. Finally, use the "mtimes" or * operator to perform matrix multiplication.
A = [1:5; 6:10; 11:15; 16:20];
row_vector = ones(1,size(A,1));
column_vector = ones(size(A,2),1);
result = row_vector*A*column_vector;
For more information about learning the basics of MATLAB®, see MATLAB Onramp.
4 commentaires
Mariam Aldeepa
le 2 Jan 2021
Why when you calculate the result multiplied the matrix "A" with another two matrices ?
Plus de réponses (11)
Alex Mcaulley
le 4 Juin 2019
I think the goal of this forum is not to do anyone's homework, but to solve generic questions about Matlab that can help more users. This exercise is very simple, anyone who has ever used Matlab could do it, so, I think the best thing we can do is help @Gaurav to know how to learn the basics of Matlab.
2 commentaires
Carlo Romagnolo
le 19 Avr 2021
Hi! I know this might be a long a shot, as this thread has been inactive for quite some time, but I was wondering if you could help me with a general question on this.
Here is my code to solve this problem:
A = [1:5; 6:10; 11:15; 16:20];
format compact
row = [1,1,1,1]
column = [1;1;1;1;1]
result = row * A * column
I was wondering if there is a better/more elegant way to answer the question which does not involve hardcoding the row and column vectors but instead uses functions.
Khom Raj Thapa Magar
le 28 Août 2020
Modifié(e) : DGM
le 21 Fév 2023
% Given
A = [1:5; 6:10; 11:15; 16:20];
row_vec = ones(1,size(A,1))
column_vec = ones(length(A),1)
result = row_vec * A * column_vec
1 commentaire
Sudhanshu Rasal
le 5 Mai 2020
Modifié(e) : DGM
le 21 Fév 2023
Simple way to do this question is
X=[1 1 1 1]
Y=[1;1;1;1;1]
result=X*A*Y
????????
3 commentaires
DGM
le 21 Fév 2023
Modifié(e) : DGM
le 21 Fév 2023
The point of writing a program is to have the computer do the work. Literally writing out the vectors manually makes as much sense as calculating the inner product on paper and writing
result = 210; % this is my entire program
Both examples will fail for obvious reasons if the size of A changes.
Tushar Parmar
le 11 Mai 2020
A = [1:5; 6:10; 11:15; 16:20]
B(1:4)=1;
f=B*A
C(1:5)=1;
C=C'
result=f*C
6 commentaires
DGM
le 21 Fév 2023
The point of writing a program is to have the computer do the work. Use size() to find the size of A; use ones() to generate the vectors programmatically.
Arakala Gautham
le 4 Avr 2020
R_vector = ones(1,size(A,1));
C_vector=ones(size(A,2),1);
result = R_vector*A*C_vector;
5 commentaires
Abhishek
le 2 Juil 2023
A = [1:5; 6:10; 11:15; 16:20];
R = (A(:,1))';
R(:)=1;
C = (A(1,:))';
C(:)=1;
result = R*A*C
%@DGM bro is this code ookay?
Rishabh Nirala
le 20 Mai 2020
Modifié(e) : DGM
le 21 Fév 2023
A = [1:5; 6:10; 11:15; 16:20];
C = [1;1;1;1;1]
R = [1 1 1 1 ]
P = R * A
result = P*C
ANSWER = 210
1 commentaire
DGM
le 21 Fév 2023
Again, the point of writing a program is to have the computer do the work. Use size() to find the size of A; use ones() to generate the vectors programmatically.
Sneham Shrikant Vaidya
le 27 Mai 2020
Modifié(e) : DGM
le 21 Fév 2023
A = [1:5; 6:10; 11:15; 16:20];
A
x = [1 1 1 1 ]
y = [1;1;1;1;1]
z = A*y
result =x*z
you can also perform this way as we know z =(lxm)*(mxn) so we first multiply A*y as their inner dimension ara same
then we obtain result matrix z that has inner dimension equal to x so now we can multiply x*z to get final ans
1 commentaire
DGM
le 21 Fév 2023
Use size() to find the size of A; use ones() to generate the vectors programmatically. Otherwise, this fails if the size of A changes.
Adding explanations to your answers is good though.
VISHWA D
le 22 Juin 2020
A = [1:5; 6:10; 11:15; 16:20];
row_vector=[1 1 1 1 1]
col_vector=[1; 1; 1; 1]
result=(row_vector*(A'))*(col_vector)
2 commentaires
lijuan wang
le 27 Août 2020
I thought the assignment has a wrong requirement, right?
we should create a vector which has the some rows as A. So it should be row_vector=[1 1 1 1]'?
DGM
le 21 Fév 2023
Modifié(e) : DGM
le 21 Fév 2023
@lijuan wang is correct. This answer creates the vectors incorrectly. Not only are they created manually in a way that would break if the size of A changes, they do not correspond to the specified dimensions of A. The result is correct, but the vectors are wrong, and the method is poor practice.
Chintan
le 21 Fév 2023
row_vector=ones(size(A(:,1)))'
coloumn_vector=ones(size(A(1,:)))'
result=row_vector*A*coloumn_vector
1 commentaire
DGM
le 21 Fév 2023
I suppose that's one way, but size() supports dimension specification, which would avoid the need to address vectors of A or to transpose anything.
Also note that the ctranspose, ' operator is the complex conjugate transpose. If you just want to reorient a vector or matrix, use transpose, .' instead.
Waseem Zafar
le 17 Sep 2023
Modifié(e) : Waseem Zafar
le 17 Sep 2023
A = [1:5; 6:10, 11:15; 16:20]
R = [1 1 1 1]
C = [1;1;1;1;1]
Z = A*C
result = R*Z
1 commentaire
DGM
le 17 Sep 2023
This example is identical to at least two other bad examples in this thread, differing only in the variable names.
You are told to use the size of A to construct two vectors. This example, and at least four others define the vectors literally instead of programmatically creating them as told. Let me be clear. You literally wrote two of the intermediate results into the script instead of making your script calculate them. If I were grading this, I would accept it no more than if you had just written
result = 210;
... because it neglects the entire point of the exercise to presuppose the input and bake the results into the script as literals.
An answer can earn its place if it demonstrates something either good or bad, but there is no value in duplicate, unformatted, unexplained answers with obvious, openly-discussed flaws. It doesn't add anything to the discussion and only serves to confuse readers who are looking for help.
Is there always room left in a thread for another answer that's not a near-duplicate? No. Sometimes it's not. Is this question completely exhausted? Not sure, but with extremely simple direct questions, it doesn't take long. If you want to answer questions, pick a thread where there is still room for a new answer.
asmaa
le 2 Fév 2024
Task
Create a row vector named d that contains sqrt(10) as the first element and pi^2 (
π2
) as the second elemen
1 commentaire
Voss
le 2 Fév 2024
Related Task
Create a row vector named d that contains -3.1 as the first element and 2.43 as the second elemen[t].
Solution:
d = [-3.1, 2.43];
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!